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Vanhegan fiendish July 13, 2012

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arkietech

Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

Posted: Fri Jul 13, 2012 5:28 am Post subject: Vanhegan fiendish July 13, 2012

Code:

*-----------*
|15.|..8|6..|
|.4.|...|.98|
|.9.|3..|1..|
|---+---+---|
|5..|2.1|.4.|
|4.1|...|8.6|
|.7.|8.4|..9|
|---+---+---|
|..4|..6|.7.|
|76.|...|.8.|
|..8|4..|.62|
*-----------*

Play/Print online

Clement

Joined: 24 Apr 2006
Posts: 1113
Location: Dar es Salaam Tanzania

Posted: Fri Jul 13, 2012 8:15 am Post subject: Vanhegan fiendish July 13, 2012

After the Basics

Code:

+------------+---------------+------------+
| 1 5 27 | 79 2479 8 | 6 3 47 |
| 23 4 237 | 6 1 257 | A257 9 8 |
| 8 9 6 | 3 2457 257 | 1 B25 457 |
+------------+---------------+------------+
| 5 8 9 | 2 6 1 | 37 4 37 |
| 4 D23 1 | 579 3579 3579 | 8 C25 6 |
| 6 7 23 | 8 35 4 | 25 1 9 |
+------------+---------------+------------+
| F239 E23 4 | 15 8 6 | 359 7 135 |
| 7 6 5 | 19 239 239 | 4 8 13 |
| 39 1 8 | 4 357 357 | 359 6 2 |
+------------+---------------+------------+

Single's Chain's on 2. A=>B=>C=>D=>E=>F; r2c1<>2 solves it.

tlanglet

Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

Posted: Fri Jul 13, 2012 1:12 pm Post subject:

An alternate solution................ 5r5c8=5r6c7-(5=3)r6c5-r6c3=r5c2-AUR(39)r79c17[(3)r7c2=(3)r4c7]-(3=7)r4c9-(47=5)r13c9; r3c8<5>

Marty R.

Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

Posted: Fri Jul 13, 2012 4:31 pm Post subject:

Code:

+------------+---------------+------------+
| 1 5 27 | 79 2479 8 | 6 3 47 |
| 23 4 237 | 6 1 257 | 257 9 8 |
| 8 9 6 | 3 2457 257 | 1 25 457 |
+------------+---------------+------------+
| 5 8 9 | 2 6 1 | 37 4 37 |
| 4 23 1 | 579 3579 3579 | 8 25 6 |
| 6 7 23 | 8 35 4 | 25 1 9 |
+------------+---------------+------------+
| 239 23 4 | 15 8 6 | 359 7 135 |
| 7 6 5 | 19 239 239 | 4 8 13 |
| 39 1 8 | 4 357 357 | 359 6 2 |
+------------+---------------+------------+

Play this puzzle online at the Daily Sudoku site

Use the DP/UR on 39 in boxes 79 to create pincers. Either r7c1=2 or r79c7=5. The latter sets r6c7=2. Transport 2 from r7c1 to r5c2; r5c8, r6c3<>2.

SudoQ

Joined: 02 Aug 2011
Posts: 127

Posted: Fri Jul 13, 2012 7:07 pm Post subject:

This pattern also solves it:

Code:

|--------------|-----------------|--------------|
| 1 5 27 | 79 2479 8 | 6 3 47 |
|(23) 4 27-3 | 6 1 257 |(2)57 9 8 |
| 8 9 6 | 3 2457 257 | 1 25 457 |
|--------------|-----------------|--------------|
| 5 8 9 | 2 6 1 | 37 4 37 |
| 4 23 1 | 579 3579 3579 | 8 25 6 |
| 6 7 (23) | 8 35 4 |(2)5 1 9 |
|--------------|-----------------|--------------|
| 239 23 4 | 15 8 6 | 359 7 135 |
| 7 6 5 | 19 239 239 | 4 8 13 |
| 39 1 8 | 4 357 357 | 359 6 2 |
|--------------|-----------------|--------------|

/SudoQ

arkietech

Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

Posted: Fri Jul 13, 2012 10:37 pm Post subject:

Another one

Code:

*-----------------------------------------------------------*
| 1 5 *27 | 79 2479 8 | 6 3 47 |
|*23 4 *237 | 6 1 257 |*257 9 8 |
| 8 9 6 | 3 2457 257 | 1 25 457 |
|-------------------+-------------------+-------------------|
| 5 8 9 | 2 6 1 | 37 4 37 |
| 4 23 1 | 579 3579 3579 | 8 25 6 |
| 6 7 3-2 | 8 35 4 |*25 1 9 |
|-------------------+-------------------+-------------------|
| 239 23 4 | 15 8 6 | 359 7 135 |
| 7 6 5 | 19 239 239 | 4 8 13 |
| 39 1 8 | 4 357 357 | 359 6 2 |
*-----------------------------------------------------------*
Empty Rectangle (ER) 2

2r1c3=r2c13-r2c7=2r6c7 => -2r3c3; stte

if r1c3 is not a 2 then r6c7 is a 2

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