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ZeroAssoluto
Joined: 05 Feb 2017 Posts: 942 Location: Rimini, Italy
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Posted: Tue Apr 12, 2022 9:11 am Post subject: Apr 12 VH |
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Hi everyone,
Code: |
+------------+-----------+-----------+
| 3 2679 5 | 1 4 279 | 67 8 26 |
| 8 4 267 | 23 5 27 | 9 1 236 |
| 1 279 27 | 239 6 8 | 37 5 4 |
+------------+-----------+-----------+
| 4 8 9 | 26 3 1 | 5 26 7 |
| 7 5 23 | 269 8 29 | 36 4 1 |
| 6 23 1 | 4 7 5 | 8 23 9 |
+------------+-----------+-----------+
| 5 1 8 | 7 2 36 | 4 9 36 |
| 9 36 4 | 8 1 36 | 2 7 5 |
| 2 367 367 | 5 9 4 | 1 36 8 |
+------------+-----------+-----------+
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Play this puzzle online at the Daily Sudoku site
Quote: | XY-Wing 2,3,7 in r3c37,r5c3 and -3 in r5c7
or
Skyscraper with number 3 in r59c3,r69c8 and -3 in r5c7,r6c2
or
2 String Kite with number 3 in r5c37,r69c8 and -3 in r9c3
2 String Kite with number 3 in r59c3,r6c28 and -3 in r9c8
or
W-Wing 3,6 in r8c2,r9c8 SL with number 3 in r6c28 and -6 in r9c23
W-Wing 3,6 in r5c7,r9c8 SL with number 3 in r59c3 and -6 in r4c8 |
Ciao Gianni |
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TomC
Joined: 30 Oct 2020 Posts: 358 Location: Wales
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Posted: Tue Apr 12, 2022 9:30 am Post subject: |
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Code: |
+-------------+-----------+-------------+
| 3 2679 5 | 1 4 279 | 67d 8 26 |
| 8 4 267 | 23 5 27 | 9 1 236 |
| 1 279 27a | 239 6 8 | 37x 5 4 |
+-------------+-----------+-------------+
| 4 8 9 | 26 3 1 | 5 26 7 |
| 7 5 23b | 269 8 29 | 36c 4 1 |
| 6 23 1 | 4 7 5 | 8 23 9 |
+-------------+-----------+-------------+
| 5 1 8 | 7 2 36 | 4 9 36 |
| 9 36 4 | 8 1 36 | 2 7 5 |
| 2 367 367 | 5 9 4 | 1 36 8 |
+-------------+-----------+-------------+
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XY chain a-d or d-a gives pincers on <7> in <a> and <d> means x is not <7> |
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Mogulmeister
Joined: 03 May 2007 Posts: 1151
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Posted: Tue Apr 12, 2022 1:45 pm Post subject: |
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Just another way of looking at a puzzle a bit differently. This technique is not a designated VH but can be useful when looking at sudokus at all levels.
Looking at Tom's grid:
Look at r3c23 and you see an almost locked pair (ANP) - both cells contain 2 and 7. However there's a 9 in r3c2 stopping a naked pair.
So, only two possibilities exist: either the naked pair <27> is true or the 9 in r3c2 is true.
If the NP is true then the <27> pair eliminate the 7 in x solving the puzzle.
If the NP is false then the <9> in r3c2 removes the 9 in r3c4 making r5c4 = 9. This makes r5c6 = 2. At this point we join Tom's loop at b = 3 and follow it out where once again the 7 in x is eliminated solving the puzzle.
Conclusion is that whether the naked pair is true or not - the answer is x can not be 7. |
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