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[cavalier]

Who can tell me how to get the "5" on 1st line,6th row per today's Sudoku?

[ravel]

------------
x5x|18x|x36
x18|x3x|x9x
x3x|x2x|xx8
------------
92x|643|8xx
xxx|215|xxx
xx1|897|x23
------------
xxx|x7x|x6x
x9x|35x|48x
1xx|x68|x5x
------------
There is a hidden pair 38 in r57c1, so r6c1 is the only place for a 5 in the first column.
[edit:] thanks to cavalier, corrected grid.

[cavalier]

I never do it from this angle. Tks! But I find some differences as following *:

x5x|18x|x36
x18|x3x|x9x
x3x|*2*|xx8
------------
92x|x43|8xx
xxx|215|xxx
xx1|89*|x23
------------
xxx|x7x|x6x
x9x|35x|48x
1xx|x68|x5x

[ravel]

Ah, thanks, i had put 6 and 3 into the 3rd instead of 4th line. I correct it above.
You can see, that the 6 in column 2 must be in r5c2 or r6c2, so it cannot be in r4c3 (same box). Therefore in row 4 only r4c4 remains for a 6. This gives the 7 in r6c6.

[cavalier]

Tks a lot! I am a beginner, seems it's lot I should learn from you.
how to get the 5 in R2C6

xx3|1xx|54x
xxx|x45|39x
452|x3x|17x
------------
32x|x1x|487
x18|4x2|963
6x4|x83|251
------------
xxx|x94|735
x4x|3x1|829
x3x|xx7|614

[ravel]

xx3|1xx|54x
xxx|x4x|39x
452|x3x|17x
------------
32x|x1x|487
x18|4x2|963
6x4|x83|251
------------
xxx|x94|735
x4x|3x1|829
x3x|xx7|614

There is a hidden pair 27 in box 2, which leaves only one place for a 5 in this box.